4x^2-29x+18=0

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Solution for 4x^2-29x+18=0 equation:



4x^2-29x+18=0
a = 4; b = -29; c = +18;
Δ = b2-4ac
Δ = -292-4·4·18
Δ = 553
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-\sqrt{553}}{2*4}=\frac{29-\sqrt{553}}{8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+\sqrt{553}}{2*4}=\frac{29+\sqrt{553}}{8} $

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